677. Map Sum Pairs

1. Question

Design a map that allows you to do the following:

  • Maps a string key to a given value.
  • Returns the sum of the values that have a key with a prefix equal to a given string.

Implement the MapSum class:

  • MapSum() Initializes the MapSum object.
  • void insert(String key, int val) Inserts the key-val pair into the map. If the key already existed, the original key-value pair will be overridden to the new one.
  • int sum(string prefix) Returns the sum of all the pairs' value whose key starts with the prefix.

2. Examples

Example 1:

Input
["MapSum", "insert", "sum", "insert", "sum"]
[[], ["apple", 3], ["ap"], ["app", 2], ["ap"]]
Output
[null, null, 3, null, 5]

Explanation
MapSum mapSum = new MapSum();
mapSum.insert("apple", 3);  
mapSum.sum("ap");           // return 3 (apple = 3)
mapSum.insert("app", 2);    
mapSum.sum("ap");           // return 5 (apple + app = 3 + 2 = 5)

3. Constraints

  • 1 <= key.length, prefix.length <= 50
  • key and prefix consist of only lowercase English letters.
  • 1 <= val <= 1000
  • At most 50 calls will be made to insert and sum.

4. References

来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/map-sum-pairs 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。

5. Solutions

class MapSum {

    HashMap<String, Integer> map;

    public MapSum() {
        map = new HashMap<>();
    }

    public void insert(String key, int val) {
        map.put(key, val);
    }

    public int sum(String prefix) {
        int sum = 0;
        for (String key : map.keySet()) {
            if (key.startsWith(prefix)) {
                sum += map.get(key);
            }
        }
        return sum;
    }
}

/**
 * Your MapSum object will be instantiated and called as such:
 * MapSum obj = new MapSum();
 * obj.insert(key,val);
 * int param_2 = obj.sum(prefix);
 */
Copyright © rootwhois.cn 2021-2022 all right reserved,powered by GitbookFile Modify: 2022-11-26 20:03:31

results matching ""

    No results matching ""