492. Construct the Rectangle
1. Question
A web developer needs to know how to design a web page's size. So, given a specific rectangular web page’s area, your job by now is to design a rectangular web page, whose length L and width W satisfy the following requirements:
- The area of the rectangular web page you designed must equal to the given target area.
- The width
W
should not be larger than the lengthL
, which meansL >= W
. - The difference between length
L
and widthW
should be as small as possible.
Return an array [L, W]
where L
and W
are the length and width of the web page you designed in sequence.
2. Examples
Example 1:
Input: area = 4
Output: [2,2]
Explanation: The target area is 4, and all the possible ways to construct it are [1,4], [2,2], [4,1].
But according to requirement 2, [1,4] is illegal; according to requirement 3, [4,1] is not optimal compared to [2,2]. So the length L is 2, and the width W is 2.
Example 2:
Input: area = 37
Output: [37,1]
Example 3:
Input: area = 122122
Output: [427,286]
3. Constraints
- 1 <= area <= 107
4. References
来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/construct-the-rectangle 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。
5. Solutions
开根解决
class Solution {
public int[] constructRectangle(int area) {
int length = (int) Math.sqrt(area);
while (area % length != 0) {
length--;
}
return new int[] { area / length, length};
}
}